Fault Current Calculation !link! -
[ I_base = \frac10 \times 10^6\sqrt3 \times 13.8 \times 10^3 = 418.4 , \textA ] [ I_f = 11.11 \times 418.4 = 4648 , \textA \quad (\textsymmetrical RMS) ]
[ Z_util = \fracS_baseS_sc = \frac101000 = 0.01 , \textpu ] fault current calculation
[ V_pu = \fracV_actualV_base, \quad I_pu = \fracI_actualI_base, \quad Z_pu = \fracZ_actualZ_base ] where ( Z_base = \fracV_base^2S_base ), ( I_base = \fracS_base\sqrt3 V_base ) (three-phase system). For a three-phase fault at a bus, the fault current magnitude is: [ I_base = \frac10 \times 10^6\sqrt3 \times 13
( S_base = 10 , \textMVA ), ( V_base, HV = 115 , \textkV ), ( V_base, LV = 13.8 , \textkV ). \textpu ] [ V_pu = \fracV_actualV_base
